Given that is a standard normal random variable, find for each situation (to 2 or 3 decimals). a. The area to the left of is .

This question is incomplete, the complete question is;

Given that is a standard normal random variable, find for each situation (to 2 or 3 decimals)

a. The area to the left of z is 0.8

b. The area to the left of z is 0.882

c. The area to the right of z is 0.8225

(Hint: Enter the positive z-value)

a) z = 0.84

b) z = 1.185

c) z = -0.925

Step-by-step explanation:

a)

area to the left of z is 0.8

Making use of the standard normal table

p( Z < z ) = 0.8

we check the the probability of 0.8 in the standard normal table

so the corresponding value of z is 0.84

p( Z < 0.84 ) = 0.8

z = 0.84

b)

area to the left of z is 0.882

Making use of the standard normal table

p( Z < z ) = 0.882

we check the the probability of 0.882 in the standard normal table

so the corresponding value of z is 1.185

p( Z < 1.185 ) = 0.882

z = 1.185

c)

area to the right of z is 0.8225

Making use of the standard normal table

p( Z > z ) = 0.8225

1 - p( Z < z ) = 0.8225

p( Z < z ) = 1 - 0.8225

p( Z < z ) = 0.1775

p( Z < -0.925 ) = 0.1775

z = -0.925

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

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step-by-step explanation:

good luck