A cereal company estimates that its monthly cost is C(x) = 400x2 + 300x and its monthly revenue is
R(x) = -0.6x3 + 900x2 – 400x + 700, where x is in thousands of
boxes sold. The profit is the difference between the revenue and the cost.
What is the profit function, P(x)?

P(x)= -0.6x^3 + 500x^2  

Step-by-step explanation:

given data

monthly cost

C(x) = 400x^2 + 300x

revenue is

R(x) = -0.6x^3 + 900x^2 – 400x + 700,

where x is in thousands of boxes sold.

we know that the profit is the difference between the revenue and the cost.

therefore P(x)=R(x)-C(x)

P(x)= -0.6x^3 + 900x^2 – 400x + 700-(400x^2 + 300x )

P(x)= -0.6x^3 + 900x^2 – 400x + 700-400x^2 - 300x

P(x)= -0.6x^3 + 500x^2  

three-fourths of an hour

36÷48=0.75

0.75=

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )