What is the equation of the line that passes through the point (5,0) and has a slope
of -1

y = -x + 5

Step-by-step explanation:

X, Y, and B is given using fomula y = m(x) + b

Subsitute those variables.

0 = -(5) + b

Solve for m.

0 = -5 + b

+5  +5

b = 5.

Then plug in the b and take out the x and y.

y = -x + 5

b

step-by-step explanation:

the word superfluous means unnecessary

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°