Walking at a speed of 3 mph, Jack gets to school in 10 minutes and arrives at school right before the class starts. Today Jack needs to be at school 4 minutes earlier. How fast does Jack need to run this morning?

Jack needs to run at a speed of 1/12 mph

Step-by-step explanation:

Mathematically;

speed = distance/ time

Distance = speed * time

10 minutes = 10/60 h = 1/6 hours

The distance to the school will be

Distance = 3 * 1/6 = 1/2 = 0.5 miles

Now, he needs to be at school 4 minutes earlier, time will now be 10 - 4 = 6 minutes

To get the speed here;

Recall that the distance from above does not change

So speed = 0.5/6 mph 0r 1/12 mph

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

step-by-step explanation:

there are 36 inches in a yard

25 : 36 = 0.69 yards (you can round to 0.70)