A rectangle has a length that is 4 ft more than its width. What are the length and
width of the rectangle if the rectangle has
a perimeter of 48 ft?

Width = W = 10 ft

Length = L = 14 ft

P = perimeter = 48 ft

Explanation:

P rectangle = 2L+ 2W
L = W + 4
P = 48

Substitute into formula:
P rectangle = 2L + 2W
48 = 2( W + 4 ) + 2W
48 = 2W + 8 + 2 W
48= 4W + 8
48 - 8 = 4W
40 = 4W
W = 40/4 = 10
W = 10

The rectangle has a length that is 4 ft more than its width : L = W + 4

Substitute : L = 10 + 4 = 14
L = 14 ft

I hope this help!!!