Please answer soon! Thanks beforehand! Ohm's law states that V=IR for a simple circuit, where V is the total voltage, I is the amount of current running through the resistor and R is the resistance of the resistor. If I=40 amperes when R=3 ohms, find the amount of current (in amperes) when the resistor has a resistance of 20 ohms. Assume voltage remains constant.

I hope this is the correct answer! :) Ohm's Law states that V=IRV=IR, where VV is the voltage in volts, II is the current in amperes, and RR is the resistance in ohms, in a simple electric circuit. Assume that as the battery is wearing out, the voltage is decreasing at 0.030.03 volts per second and as the resistor heats up, the resistance increases at 0.040.04 ohms per second. So when the resistance is 200200 oms and the current is 0.040.04 amperes, at what rate is the current changing?

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answer: it is 1: 47 pm

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