While on spring break, Kayla decided she wanted to go parasailing She was held at a constant angle above the water by a large tow rope attached to the back of the boat. The length of the tow rope is 240 meters. If the angle of the rope keeps Kayla at a horizontal distance of 181 meters away from the boat, how high above the boat is Kayla?

157.6m

Step-by-step explanation:

Given

Horizontal distance = 181m

Length of the rope =240m

To know how high above Kayla was, we will use the Pythagoras theorem.

According to the theorem;

d² = x²+y²

x is the horizontal distance

y is the vertical distance

d is the length of the rope

Substitute

240² = 181²+y²

y² = 240²-181²

y² = 24839

y = √24839

y = 157.6m

Hence the boat is 157.6m above Kayla

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.