The swimming pool is open when the high temperature is higher than 20°C. Laney tried to swim on Monday and Thursday the pool was open on Monday but it was closed on Thursday the high temperature it was 30°C on Monday but decreased at a constant rate in the next three days. What is an any quality to determine the rate of temperature decrease in degrees Celsius per day from monday to thursday

30 - 3t ≤ 20

Step-by-step explanation:

Given that :

Pool is open when high temperature is higher than 20°C

From 30°C ; temperature decreased at a constant rate in the next three days ; that is the daily fall in temperature for 3 days is the same.

Let the fall or decrease in temperature = t

Constant decrease for 3 days = 3t

Change in temperature over 3 days :

Initial temperature - constant decrease

30°C - 3t

Hence, inequality to determine rate of temperature decrease :

30 - 3t ≤ 20

the slope of the first function is -3. (3/1)

the slope of the second function is 1. (13-10/6-3).

since |-3| is greater than |1|, the function with the steepest slope is the first.