A model rocket is launched upward at a speed of 128 feet per second from a platform 15 +feet above the ground. Choose a statement about the rocket's flight The rocket will reach its maximum height after 7 seconds. The rocket will reach its maximum height after 5 seconds. The maximum height that the rocket will reach is 191 feet. The maximum height that the rocket will reach is 271 feet.

The maximum height that the rocket will reach is 271 feet.

Step-by-step explanation:

We first calculate the time, t it takes the rocket to reach maximum height from v = u - gt. Since u = initial velocity = 128 ft/s, v = velocity at maximum height = 0  ft/s and g = acceleration due to gravity = 32 ft/s².

So, v = u - gt.

t = (u - v)/g

= (128 ft/s - 0 ft/s)/32 ft/s²

= 128 ft/s ÷ 32 ft/s²

= 4 s.

We calculate the maximum height from

y - y₀ = ut - 1/2gt² where y₀ = 15 ft and all other variables are as above.

Substituting these values into the equation, we have

y - y₀ = (u - 1/2gt)t

y - 15 ft = (128 ft/s - 1/2 × 32 ft/s² × 4 s) × 4 s

y - 15 ft = (128 ft/s - 64 ft/s)4 s

y - 15 ft = 64 ft/s × 4 s

y - 15 ft = 256 ft

y = 256 ft + 15 ft

y = 271 ft

So, the maximum height that the rocket will reach is 271 feet.

the fist one is not equalvalent but i think th second one isand the third isnt definetly or the last one is i think. hope this !

step-by-step explanation: