Write the equation of a line in point Slope form that passes through the points (-8,-3) and (2,2)

The midpoint of the points (2,8) and (0,4) is given by:

(

2

x

1

+x

2

,

2

y

1

+y

2

)=(

2

2+0

,

2

8+4

)=(

2

2

,

2

12

)=(1,6)

We must must transform the standard form equation −3x+6y=5 into a slope-intercept form equation (y=mx+b) to find its slope.

−3x+6y=5 (Subtract 3x on both sides.)

6y=3x+5 (Divide both sides by 6.)

y=

6

3

x+

6

5

y=

2

1

x+

6

5

The slope of our first line is equal to

2

1

. Perpendicular lines have negative reciprocal slopes, so if the slope of one is x, the slope of the other is

x

1

.

The negative reciprocal of

2

1

is equal to −2, therefore, −2 is the slope of our line.

Since the equation of line passing through the midpoint (1,6), therefore, substitute the given point in the equation y=−2x+b:

6=(−2×1)+b

6=−2+b

b=6+2=8

Substitute this value for b in the equation y=−2x+b:

y=−2x+8

Hence, the equation of the line is y=−2x+8.

Step-by-step explanation:

make me as brain liest

r and t.

both are 64 degrees.