Wish someone can do this for me.

Given : Two inequality is given to us . The inequality is v + 8 ≤ -4 and v - 6 ≥ 10 .

To Find : To write those two inequality as a compound inequality with integers .

Solution: First inequality given to us is v + 8 ≤ -4 . So let's simplify it ;

⇒ v + 8 ≤ -4 .

⇒ v ≤ -4 - 8.

⇒ v ≤ -12 .

Now , on simplifying the second inequality ,

⇒ v - 6 ≥ 10 .

⇒ v ≥ 10 + 6.

⇒ v ≥ 16 .

Hence the required answer will be :

First one implies that v is less than or equal to -12 whereas the second one implies that v is greater than or equal to 16 .

true? is that what you're asking or do you mean something else?

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11