Find two numbers if their ratio is 9:11 and their difference is 6.

Step-by-step explanation:

27,33

9*3 is 27

11*3 is 33

33-27 is 6

i only have one, sorry!

Step-by-step explanation:

Let the larger number = y

Let the smaller number = x

x/y = 9/11

y - x = 6

Add x to both sides of the second equation

y = 6 + x

Substitute into the first equation

x/(x + 6) = 9/11

Cross multiply

11x = 9(x + 6)

Remove the brackets

11x = 9x + 54

Subtract 9x from both sides.

2x = 54

x = 54/2

x = 27

y = 27 + 6

y = 33

(27,33)

The way I've done it, there isn't a second pair.

I suppose you could do it this way.

9/11 = -27/-33

-27 - - 33 = 6

So the second pair could be

(-27, - 33)

45

step-by-step explanation:

a is the right answer