HELP ME PLEASE!!
Describe how you can use the factors of a quadratic function to find its zeros.

Factorising the equation into brackets can help you identify where the x-intercepts are (where the function cuts the x-axis)

Step-by-step explanation:

When you factorise the equation it would look something like this:

(x + a)(x + b) = 0

This also means:

x + a = 0        and        x + b = 0

x = -a             and        x = -b

Example:

Find where the function y = 2x² + 8x + 6 cuts the x-axis

Factorise the 2 out (highest common factor)

x² + 4x + 3 = 0

(x + 1)(x + 3) = 0

x = -1 or -3

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

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