According to Boyle's Law, if the temperature of a confined gas is held fixed, then the product of the pressure P and the volume V is a constant, suppose that, for a certain gas, PV=800 where P is measured in pounds per square inch and V is measured in cubic inches. Answer the following: (this is calculus) A) Find the average rate of change of P as V increases from 200in^3 to 250in^3.
B) Express V as a function of P and show that the instantaneous rate of change of V with respect to P is inversely proportional to the square of P.

Part(a): The average rate of change of is

Part(b): The required answer is

Part(a):

Given,

Differentiating the above equation with respect to .

Now, at and

At and

Hence, we can write,

at we get,

Again at we get,

So, the average rate of change of is,

Part(b):

Given, then,

Now,

Then the above implies,

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If PV = 800, then P can be written as a function of V,

P(V) = 800 / V

(a) The average rate of change of P as V increases from 200 to 250 in³ is then

(P (250) - P (200)) / (250 in³ - 200 in³) = (3.2 lb/in² - 4lb/in²) / (50 in³)

... = -0.016 (lb/in²)/in³

(Or -0.016 lb/in⁵, but I figure writing the rate as (units of pressure) per (unit volume) makes more sense.)

(b) We can also write V as a function of P :

V(P) = 800 / P

Take the derivative:

V'(P) = - 800 / P²

which immediately demonstrates that V'(P) ∝ 1 / P², as required. (The fish-looking symbol, ∝, means "is proportional to".)

If differentiating is supposed to be more involved, you can use the limit definition:

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.