While on spring break, Kayla decided she wanted to go parasailing She was held at a constant angle above the water by a large tow rope attached to the back of the boat. The length of the tow rope is 240 meters. If the angle of the rope keeps Kayla at a horizontal distance of 181 meters away from the boat, how high above the boat is Kayla?

Option (4)

Step-by-step explanation:

From the figure attached,

Length of the rope holding Kayla to the boat = 240 meters

Horizontal distance of Kayla from the boat = x = 181 meters

Let the distance of Kayla above the boat = y meters

Triangle formed is a right triangle. Therefore, by applying Pythagoras theorem in the given triangle,

x² + y² = (240)²

(181)² + y² = (240)²

y =

  =

  = 157.6 meters

Therefore, vertical distance between Kayla and boat is 157.6 meters.

Option (4) will be the answer.

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.