Find three consecutive odd integers whose sum is -45. Find the largest
integer

x = the first integer.

x + 2 = the second integer.

x + 4 = the third integer.

x + x + 2 + x + 4 = -45

Combine like terms.

3x + 6 = -45

Subtract 6 from both sides.

3x = -51

Divide both sides by 3

x = -17

x + 2 = -17 + 2 = -15

x + 4 = -17 + 4 = -13

The largest integer is -13

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.