Solve the system of equation

x= 3, y= 8

or x= -1, y= 0

Step-by-step explanation:

y= 2x² -2x -4 (1)

y -2x= 2

y= 2x +2 (2)

Substitute (1) into (2):

2x² -2x -4= 2x +2

2x² -2x -4 -2x -2= 0 (bring all terms to the left)

2x² -4x -6= 0 (simplify)

x² -2x -3= 0 (÷2 on both sides)

(x -3)(x +1)= 0 (factorise)

x -3= 0 or x +1= 0

x= 3 or x= -1

Substitute into (2):

y= 2(3) +2 or y= 2(-1) +2

y= 6 +2 or y= -2 +2

y= 8 or y= 0

1. a^4+8a^3+24a^2+32a+16

2.y^8+8y^7+28y^6+56y^5+70y^4+56y^3+28y^2+8y+1

3.x^6-3x^4y^2+3x^2y^4-y^6