You hit a golf ball into the air from a height of inches above the ground, with an initial velocity of 85 ft/s. The function is h= -16t^2+85t+1/12, models the height, in feet, of the ball at time ¨t¨, in seconds. Will the ball ever reach a height of 125 ft?

The ball will not get up to 125 ft

Step-by-step explanation:

The initial velocity of the golf ball = 85 ft/s

The function for the height, h, in feet, of the golf ball is h = -16·t² + 85·t + 1/12

Where;

t = The time in seconds of flight of the golf ball

We have at maximum height, dh/dt = 0, which gives;

dh/dt = d(-16·t² + 85·t + 1/12)/dt = 0

-32·t + 85 = 0

t = 85/32

Given that d²h/dt² = d(-32·t + 85)/dt = -32 which is negative, the obtained point, t = 85/32, above is a maximum point

Substituting the value of t at the maximum into the function for the height h, to obtain the value for the maximum height, we have;

h = h(85/32) = -16 × (85/32)² + 85× (85/32) + 1/12  ≈ 112.974

The maximum height reached = h = 112.974 ft.

The maximum height reached ≈ 112.974 ft

Therefore, the ball will not get up to 125 ft.

the answer is a i belaeve atleast thats what my calculator just gfave me

step-by-step explanation:

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3