What is an equation of the line that passes through the points (3, 8) and (1,0)?

y = 4x - 4

Step-by-step explanation:

first, find the slope:

y2 - y1/ x2 -x1

8 - 0/ 3 - 1 = 4

no plug in your slope and one of the points to find the b:

y = mx+b

0 = 4 (1) + b

b= -4

so

y = 4x - 4

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°