Charlie is at an amusement park that has 18 different rides. Each ride costs $1.75. The function C(r) = 1.75r represents the total amount of money that Charlie will spend if he goes on r rides, but he never goes on the same one more than once. What domain and range are reasonable for the function? A. D : 0 ≤ r ≤ 31.5 R : 0 ≤ C(r) ≤ 18 B. D : 0 ≤ r ≤ 18 R : 0 ≤ C(r) ≤ 31.5 C. D : 1 ≤ r ≤ 18 R : 1.75 ≤ C(r) ≤ 31.5 D. D : 0 ≤ r ≤ 18 R : 18 ≤ C(r) ≤ 31.5

Domain= [0,18], Range = [0,31.50]

Step-by-step explanation:

If Charlie will only go to a single ride one time the possible rides he could go on would be 0 rides to all 18 rides for a domain of [0,18]. The output of the maximum and minimum x values would give us 0 dollars for riding 0 rides and 31.50 for riding all 18 (1.75 *0 = 0) and (1.75*18 = 31.50) so the range is [0, 31.50]

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.