Six different colored dice are rolled. Of interest is the number of dice that show a one. In words, define the random variable X. List the values that X may take on. Give the distribution of X. X ~ (,) On average, how many dice would you expect to show a one? Find the probability that all six dice show a one. Is it more likely that three or that four dice will show a one? Use numbers to justify your answer numerically.

Step-by-step explanation:

Six dice (each of a different color) are rolled. Since the number of times the 6 dice were rolled isn't stated, take it to be 1.

Hence, 6 dice are rolled at once for this experiment.

Of interest is the number of dice that show a "one". In other words, the variable in question (X) is:

The number of dots that show on the upward face of the rolled dice.

The values that X may take on are:

1  2  3  4  5  6

On average, how many dice would you expect to show a one?

One die.

How is this gotten? By finding the probability that a one or one dot appears when the 6 dice are rolled at once. Since there are 6 dice in number, and each die has the same 6 faces containing dots, the probability of getting a one is 1/6. In this case, one out of 6 dice is expected to show one dot.

Find the probability that all six dice show a dot in just one toss.

Logically, this probability is going to be very small! It is almost impossible for all 6 dice to land on the same face in just a single toss. In other words, expect many decimal places in the probability figure.

1/6 divided by 6  = 0.167/6  = 0.028 approximated to three decimal places.

This would also represent the probability that 2 dots, 3 dots, or any other number of dots appears on all dice in one toss!

Is it more likely (in this experiment) that 3 or 4 dice will show a one (a single dot)?

The answer is yes! It is more likely that 3 or 4 dice (instead of all 6) will show a one or will show the same number of dots.

Kudos!

c > -10.55

step-by-step explanation: