Mathematics, 17.10.2020 14:01 nataliamontirl6079
Rewrite by completing the square 2x^2+7x+6=0
Answers: 2
![2x^2+7x+6=0\\\\2(x^2+\frac72x+3)=0\\\\2[x^2+2\cdot x\cdot\frac74+(\frac74)^2-(\frac74)^2+3]=0\\\\2[x^2+2\cdot x\cdot\frac74+(\frac74)^2]-2(\frac74)^2+6=0 \\\\2(x+\frac74)^2-2\cdot\frac{49}{16}+6=0\\\\2(x+\frac74)^2-\frac{49}8+\frac{48}8=0\\\\2(x+\frac74)^2-\frac18=0](/tpl/images/0815/8368/45325.png)
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Rewrite by completing the square 2x^2+7x+6=0...
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