(a) If A is the area of a circle with radius r and the circle expands as time passes, find dA dt in terms of dr dt . dA dt

Step-by-step explanation:

The question is incomplete. Here is the complete question.

If A is the area of a circle with radius r and the circle expands as time passes, find dA/dt in terms of dr/dt. dA dt = dr dt (b) Suppose oil spills from a ruptured tanker and spreads in a circular pattern. If the radius of the oil spill increases at a constant rate of 1 m/s, how fast is the area of the spill increasing when the radius is 25 m?

Area of the circle A = πr²

dA/dr = 2πr where r is the radius of the circle

dA/dt = dA/dr * dr/dt

dr/dt is the rate of increase in radius of the oil spill.

Given

dr/dt = 1m/s

radius r = 25m

Substitute into the formula above;

dA/dt = dA/dr * dr/dt

dA/dt = 2πr * 1

dA/dt = 2π(25) * 1

dA/dt = 50πm²/s

dA/dt = 157.1m²/s

Hence the area of the spill is increasing at the rate of 157.1m²/s

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

answer: what in the world is this

step-by-step explanation: