Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (-3,-3);y=-3x-2 y=−3x+2
Write an equation for the line in slope-intercept form.

y = –3x – 6

Step-by-step explanation:

We'll begin by obtaining the slope of the equation y = –3x – 2.

This can be obtained by comparing

y = –3x – 2 with y = mx + c

Thus, the slope (m) of the equation

y = –3x – 2 is –3.

Next, we shall determine the slope of the equation parallel to line with equation y = –3x – 2.

This is illustrated below:

For parallel lines, the slope are related as follow:

m1 = m2

m1 = –3

m2 = m1 = –3.

Finally, we shall determine the equation as follow:

Coordinate = (–3, –3)

x1 coordinate = –3

y1 coordinate = –3

Slope (m) = –3

y –y1 = m(x – x1)

y – (–3) = –3 (x – (–3))

y + 3 = –3 (x + 3)

y + 3 = –3x – 3

Rearrange

y = –3x – 3 – 3

y = –3x – 6

Thus, the equation parallel to the line is y = –3x – 6

its line 2 i just added the rest or else it wouldn't let me answer

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9