F(x)=(x-1)^2(x+3)^3(x+1) the zero located at x=1 has a multiplicity of ( blank1 ) and the zero located at x=-3 has a multiplicity of ( blank2 ). The graph of the function will touch, but not cross , the axis at an x-value of (blank3)

blank1: 1,2,3
blank2:1,2,3
blank3: 1 only, -3 and 1 only, -3 only, (-3,-1 and 1),-1 only

do you have the measurements?

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

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step-by-step explanation: