Help show work assig 8
(a)solve the inequality
(b)graph the solution on the real number line.
(c)write the solution in interval notation.
29
30
31
32
33

 see below

Step-by-step explanation:

29) -5x ≥  30

    ÷ -5 ↓ ÷ -5

        x  ≤ -6

Graph:       ← ·

                            -6

Interval Notation: (-∞, 6]

30) -4x <  -40

    ÷ -4 ↓ ÷ -4

        x  >   10

Graph:       o→

                10

Interval Notation: (10, ∞)

31) 2x - 5 ≥  -11

         +5    +5

     2x      ≥  -6

    ÷ 2       ÷ 2

        x   ≥   -3

Graph:       · →

                -3

Interval Notation: [-3, ∞)

32) 8 - 3x > 20

    -8         -8

        -3x >  12

     ÷ -3  ↓ ÷ -3

          x  <  -4

Graph:       ←o

                            -4

Interval Notation: (-∞, -4)

33) 4x - 11 < 7x + 4

    -7x       -7x      

   -3x  - 11  <   4

          + 11   +11    

   -3x       <    15

 ÷ -3      ↓ ÷ -3

         x  >    -5

Graph:       o→

                  -5

Interval Notation: (-5, ∞)

answer: sensy

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b