Use the quadratic formula to complete the table. To verify your solutions, graph the equations. thank you so much for your help :)

1) Value of Discriminant: -32

Solution Value(s):

x = -2/3 + 2√2i/3

x = -2/3 - 2√2i/3

2) Value of Discriminant: -44

Solution Value(s):

x = -1/3 + √11i/3

x = -1/3 - √11i/3

Step-by-step explanation:

The Discriminant is the part of the Quadratic Formula that is under the square root symbol.

If the Discriminant > 0 there are 2 real solutions.

If the Discriminant = 0 there is 1 real solution.

If the Discriminant < 0 there are 2 imaginary solutions.

Equation 1:

3x² + 4x + 4 = 0

Plug this into the Quadratic Formula and solve:

x = -4 ± √-32 all over 6

Value of Discriminant: -32

Obviously, this can be simplified more, but for now, all you need is what is under the square root. Since it is less than 0, there are going to be 2 imaginary solutions.

Continue simplifying to get to the Solution Values. You will end up here:

x = -2/3 ± 2√2i/3

Your two imaginary solutions are:

x = -2/3 + 2√2i/3

x = -2/3 - 2√2i/3

*Note: 2√2i is ALL over 3, not just the √2i*

You can convert this to decimal if you need (but I don’t suggest it):

x = -0.66666 + 0.942809i

x = -0.66666 - 0.942809i

Equation 2:

3x² + 2x + 4 = 0

Plug this into the Quadratic Formula and solve:

x = -2 ± √-44 all over 6

Value of Discriminant: -44

Obviously, this can be simplified more, but for now, all you need is what is under the square root. Since it is less than 0, there are going to be 2 imaginary solutions again.

Continue simplifying to get to the Solution Values. You will end up here:

x = -1/3 ± √11i/3

Your two imaginary solutions are:

x = -1/3 + √11i/3

x = -1/3 - √11i/3

You can convert this to decimal if you need (but I don’t suggest it):

x = -0.33333 + 1.10554i

x = -0.33333 - 1.10554i

Hope this helps!

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

answer:

your answer is: c. 196 7/8 in^3.