12x+8y=28 in slope intercept form

Step-by-step explanation:

The given expression is:

       12x + 8y = 28

Problem;

 Express in slope-intercept format;

   Solution:

The equation of a straight line is given as;

     y = mx + c

where y is the y-coordinate

          m is the slope

          x is the x-coordinate

          c is the intercept

 To solve this problem simply express the given equation as that of a straight line.

     12x + 8y = 28  in the form y = mx + c

      12x + 8y = 28  

   take 12x to the other side;

          8y  = 28 - 12x

divide by 8 to isolate the y;

            y  =

Re-arranging gives;

           y =

This is the slope-intercept form.  

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!