An empty erlenmeyer flask that weighs 245.8 g is filled with 125 mL of carbon tetrachloride . The weight of the flask and carbon tetrachloride is found to be 444.6 g. From this information , calculate the density of carbon tetrachloride .

The density of carbon tetrachloride is 1.59 grams per milliliter.

Given that an empty erlenmeyer flask that weighs 245.8 g is filled with 125 mL of carbon tetrachloride, and the weight of the flask and carbon tetrachloride is found to be 444.6 g, to determine the density of carbon tetrachloride the following calculation must be performed:

Subtract the weight of the empty flask from the weight of the full flask, and then divide this result by 125 (the milliliters of carbon tetrachloride).

Therefore, the density of carbon tetrachloride is 1.59 grams per milliliter.

Learn more in link

The density is 1.59 g/mL. Therefore, the substance will NOT float in water.

Step-by-step explanation:

The following data were obtained from the question:

Mass of empty flask = 245.8 g

Mass of flask + CCl₄ = 444.6 g

Volume of CCl₄ = 125 mL

Density of CCl₄ =?

Next, we shall determine the mass of carbon tetrachloride, CCl₄. This can be obtained as follow:

Mass of empty flask = 245.8 g

Mass of flask + CCl₄ = 444.6 g

Mass of CCl₄ =.?

Mass of CCl₄ = (Mass of flask + CCl₄) – (Mass of empty flask)

Mass of CCl₄ = 444.6 – 245.8

Mass of CCl₄ = 198.8 g

Finally, we shall determine the density of carbon tetrachloride, CCl₄ as follow:

Mass of CCl₄ = 198.8 g

Volume of CCl₄ = 125 mL

Density of CCl₄ =?

Density = mass / volume

Density of CCl₄ = 198.8 / 125

Density of CCl₄ = 1.59 g/mL

The density of water is 1 g/mL. Since the density of carbon tetrachloride, CCl₄ (i.e 1.59 g/mL) is bigger than that of water, the substance will not float in water.

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."