A hiker started the day at an elevation of 800 feet. He climbed 200 feet in elevation to his first rest stop, hiked down 400 feet in elevation to his second rest stop, and climbed 500 feet in elevation to his third rest stop. What is the average elevation of his three rest stops

The average elevation of his three rest stop is 900 ft

Step-by-step explanation:

The elevation at which the hiker started = 800 feet

The extra height to which he climbed on his first rest stop = 200 feet

The height down which he climbed to his second rest stop = 400 feet

The height to which he then climbed to his third rest stop = 500 ft

Given that the hiker started at 800 ft, we have;

His height at his first rest stop = 800 + 200 = 1,000 ft

His height at his second rest stop = 1000 - 400 = 600 ft

His height at his third rest stop = 600 + 500 = 1,100 ft

Therefore, the average elevation, hₐ, of his three rest stop is given as follows;

hₐ = (The sum of the three elevation)/(The number of elevation)

hₐ = (1,000 ft + 600 ft + 1,100 ft)/(3) = (2700 ft)/3  = 900 ft

The average elevation of his three rest stop = 900 ft.

the answer is 31.27mph