What is the equation of the line that passes through (0, -2) and has a slope of 0? y = -2 y = 2 x = 2 user: the slope of a line is -1/3. find the slope of a line that is perpendicular to this line. -3 1/3 3

Equation of a line is given by y - y1 = m(x - x1); where m is thw slope.
y - (-2) = 0(x - 0)
y = -2

For perpendicular lines, m2 = -1/m1
so, m2 = -1 / -1/3 = 3
Therefore the slope of a line perpendicular to the line is 3.

It is 5.8 you add all of the up to equat 180 then solve the equation