Mathematics, 16.10.2020 15:01 maybaby9625
Solve the system of equations.
3x + 3y + 62 = 3
3x + 2y + 62 = 7
4x + 4y + 72 = 4
a. (x = 5, y = - 4,2 = 0)
b. (x = 4, y = -3, 2 = 1)
c. (x = 6, y=-5,2=-1)
d. (x = 7, y=-6, z = 2)
Answers: 1
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Mathematics, 22.06.2019 03:30, mbonham481
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Answers: 2
Solve the system of equations.
3x + 3y + 62 = 3
3x + 2y + 62 = 7
4x + 4y + 72 = 4
...
3x + 2y + 62 = 7
4x + 4y + 72 = 4
...
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