Find the value(s) of "k" that will cause the equation 4x^2 +kx + 4 to have one real solution.

 k = {8, -8}

Step-by-step explanation:

In order for a quadratic equation to have exactly one solution, the discriminant must equal zero.       →        b² - 4ac = 0

  4x² + kx + 4 = 0

  ↓       ↓      ↓

a=4    b=k    c=4

b² - 4ac = 0

k² - 4(4)(4) = 0

k²             = 64

           k = √64

           k = ± 8

w

step-by-step explanation:

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9