Let y=f(x) be a twice - differentiable function such that f(1)=2 and dy/dx =y^3+3. What is the value of d^2y/dx^2 at x=1?

i dont know sorry

step-by-step explanation:

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

b if for most of the graph

d if y intercept

step-by-step explanation:

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x