A train goes from Springfield, MA to Boston at a speed of 40 mph. On the return journey it moves at a speed of 80 mph. If the return journey takes an hour less than the outward journey, what is the average speed overall of the train?

The answer is 53.3333333

Step-by-step explanation:

first you know that the speed on the way there is 40 mph and the back is 80

lets call the time x On the way there the time would just be X on the way back it would be x-1 because it took one less our

to calculate the distance you need to do speed times time therefor the distance on the way there would be 40x and the way back would be 80x-80

Then I made an equation 40x=80x-80 X=2

so the distance would be 80 miles but to find average speed you need to do total distance over total time so it would be 160 over 3 because the time is 2x-2 x=2 so thats 3

Hope this helps

da freeck kinda math is this just drop out

step-by-step explanation: