David begins the summer with a savings of $54.00 more than Fatima. David’s job pays $8.25 per hour. Fatima’s job pays $9.75. If they both work the same amount of
time each day, how many hours of work will it take David to have as much money as
Fatima? Write an inequality and then solve.

The required inequality is 8.25x + 54 = 9.75x

It will take 36 hours for David to have as much as Fatima.

David :

Initial saving = 54

Pay per hour = $8.25

Fatima :

Pay per hour = $9.75

Let number of hours worked = x

David's total = $8.25x + 54

Fatima's total = 9.75x

In other to have the same amount :

8.25x + 54 = 9.75x

Collect like terms :

8.25x - 9.75x = - 54

-1.5x = - 54

x = - 54 / - 1.5

x = 36

Hence, it will take 36 hours for David to have as much as Fatima.

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36 hours (1 1/2 days, 351$ )

Step-by-step explanation:

create a linear system and solve.

8.25x + 54 = 9.75x

-8.25x -8.25x

54 = 1.5x

1.5 x = 54

÷ 1.5. ÷1.5

x = 36.

if you want to know how much money they will have at this time, just substitute the x value that you solved for back into the equation

x = 36 -> 8.25(x) + 54 = 9.75(x)

8.25(36) + 54 = 9.75(36)

297 + 54 = 351

351 = 351

David's budget >= 54$

Fatima's budget >= 0$

table a is wierd

step-by-step explanation:

6*f