P SOMEONE HELP ME For a field trip 23 students rode in cars and the rest filled five buses. How many students were in each bus if 288 students were on the trip?

First, you start with the equation:

9

x

+

4

=

472

Since four students rode in cars, you want to eliminate this part of the problem to find how many students actually rode in the buses

So you would subtract

4

from both sides and get:

9

x

=

468

Finally, you would divide both sides by

9

and get

52

students on each bus

Step-by-step explanation: First, you start with the equation:

9

x

+

4

=

472

Since four students rode in cars, you want to eliminate this part of the problem to find how many students actually rode in the buses

So you would subtract

4

from both sides and get:

9

x

=

468

Finally, you would divide both sides by

9

and get

52

students on each bus

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.