Suppose a laboratory has a 38 g sample of polonium-210. the half-life of polonium-210 is about 138 days. how many half-lives of polonium-210 occur in 1104 days? how much polonium is in the sample 1104 days later?
9 ; 0.07 g
8 ; 2,2622 g
8 ; 4.75 g
8 ; 0.15 g

0.15 g of Polonium will be in the sample 1104 days later.

Step-by-step explanation:

The exponential function for decay is,

Where,

y(t) = the amount after time t,

a = initial amount = 38 g

r = rate of decay = 50% = 0.50 (as the sample is getting halved each time)

t = time period = (as we have to convert the time in terms of half lifes)

Putting all the values,

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

if x decreases by 4 then y increases by 10

step-by-step explanation: