Please help me, thank you

9514 1404 393

Step-by-step explanation:

1. We can rewrite the second equation to solve for z:

  z = x +3y -16

Then we can substitute the last equation for y:

  z = x +3(-4x +4) -16

  z = x -12x +12 -16

  z = -11x -4

The first equation tells us x = 0, so ...

  z = -11·0 -4

  z = -4

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2. Substituting the first equation into the second gives ...

  x -3(-5) = 13

  x + 15 = 13 . . . . simplify

  x = -2 . . . . . . . . subtract 15

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3. The first inequality eliminates the 2nd choice.

The last inequality eliminates the 3rd and 4th choices.

The 1st choice satisfies the 2nd inequality, so that is your

  3 ≥ 3·4 -5 . . . use (4, 3) in the second inequality

  3 ≥ 3 . . . . . true

  (x, y) = (4, 3) is a solution

i cant see the pictures can you re post them>

Step-by-step explanation:

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

5x+10 is the correct one

hope this