Lines A and C are having a slope of (5/2) and line E may have the slope of (5/2).
Step-by-step explanation:
Given information:
Line A,B,C,D and E having different slopes;
Now as we know that equation of the line is:
![y=mx+c](/tpl/images/0807/6421/c0c58.png)
where, m is the slope of the line
Now, Also ![dy/dx=m](/tpl/images/0807/6421/75ab1.png)
Hence, the slope of the line can also be calculated according to that.
Now, as given in the graph:
Line A is having ![dy=10\; \text {and} \; dx =4](/tpl/images/0807/6421/015f3.png)
Hence slope of line A
![dy/dx(A)=5/2](/tpl/images/0807/6421/7d876.png)
Similarly:
Line B is having slope of (4/2)
Line C is having slope of (5/2)
Line D is not having slope of (5/2)
And Line E may have the slope of (5/2).
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