Compute the estimated regression's prediction for the average score of students given 98, 129, or 159 minutes to complete the exam. Given 98 minutes, the estimated regression's prediction for the average score of students is 91.94 .
Given 129 minutes, the estimated regression's prediction for the average score of students is 108.37
Given 159 minutes, the estimated regression's prediction for the average score of students is 124.27 (Round your responses to two decimal places.)
Compute the estimated gain in score for a student who is given an additional 32 minutes on the exam.
The estimated gain in score for a student who is given an additional 32 minutes on the exam is (Round your response to two decimal places.)

The estimated gain in score for a student who is given an additional 32 minutes on the exam is 16.96

Step-by-step explanation:

The estimated regression prediction is given by:

Where x denotes the time

y denotes the average score

A)

Substitute x = 98

B)

Substitute x = 129

C)

Substitute x = 159

D)the estimated gain in score for a student who is given an additional 32 minutes on the exam.

So, the estimated gain in score for a student who is given an additional 32 minutes on the exam is 16.96

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.