Write the first 4 terms of the arithmetic sequence With first term 37 and common difference 9

Answers:

first term = 37

second term = 46

third term = 55

fourth term = 64

Explanation:

Start at 37. Add 9 to this term to get the second term. Add 9 to that result to get the next term, and so on.

first term = 37

second term = 37+9 = 46

third term = 46+9 = 55

fourth term = 55+9 = 64

The nth term formula is

a(n) = 9n+28

It can be found by plugging a = 37 and d = 9 into the general form

a(n) = a + d*(n-1)

12/11c

or

12

c

11