Yuto left his house at 10 a. M. To go for a bike ride. By the time Yuto's sister Riko left their house, Yuto was already 5.25 miles along the path they both took. If Yuto's average speed was 0.25 per minute and Riko's average speed was 0.35 per minute, over what time period in minutes, t, starting from when Riko left the house, will Riko be Behind her brother?

The time period will be ;

10 am to 10 : 52 am

(Then she will catch up at exactly 10:52 am , 30 seconds)

Step-by-step explanation:

In this question, what we simply want to calculate is the amount of time it will take Riko to cover same distance as Yuto.

Mathematically, at any point in time;

Speed = distance/time

Let the time we are looking for be x minutes

At x minutes , Riko will be at a distance of 0.35 * x = 0.35x miles

At x minutes, Yuto will be at a distance of 5.25 miles + 0.25 * x = (5.25 + 0.25x) mikes

Kindly note that, at the time x minutes, the distance covered would have been equal;

Thus;

0.35x = 5.25 + 0.25x

0.35x -0.25x = 5.25

0.1x = 5.25

x = 5.25/0.1

x = 52.5 minutes

Over a time period of 52.5 minutes, Riko will be behind her brother ;

Since Yuto left at 10 am, the time period will be ;

10am to 10:52 am

12

step-by-step explanation:

a triangle's   full angle is 180 degrees so 180 - 156 = 24. 24/2=12

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: