Which of the following relations are not functions? Select all that apply.  {(1, 3), (3, 7), (5, 11), (7, 15), (9, 19)}  {(1, 3), (1, 7), (5, 11), (5, 15), (9, 19)}  {(−2, 4), (−1, 1), (0, 0), (1, 1), (2, 4)}  {(2, 4), (1, 1), (0, 0), (1,−1), (2, −4)}  {(6, 3), (4, 1), (2, 1), (0,−1), (−2,−3)}  {(1, 3), (3, 7), (3, 11), (7, 15), (9, 19)}  {(1, 3), (3, 7), (5, 11), (9, 15), (9, 19)}

Given:

7 relations are given.

To find:

The relation which is not a function.

Step-by-step explanation:

A relation is called function if there exist unique output for each input.

It means, each x-value has only one y-value.

{(1, 3), (3, 7), (5, 11), (7, 15), (9, 19)}, it is a function.

{(1, 3), (1, 7), (5, 11), (5, 15), (9, 19)}, it is not a function because there exist two y-values y=3 and y=7 at x=1.

{(−2, 4), (−1, 1), (0, 0), (1, 1), (2, 4)}, it is a function.

{(2, 4), (1, 1), (0, 0), (1,−1), (2, −4)},it is not a function because there exist two y-values y=4 and y=-4 at x=2.

{(6, 3), (4, 1), (2, 1), (0,−1), (−2,−3)}, it is a function.

{(1, 3), (3, 7), (3, 11), (7, 15), (9, 19)}, it is not a function because there exist two y-values y=7 and y=11 at x=3.

{(1, 3), (3, 7), (5, 11), (9, 15), (9, 19)}, it is not a function because there exist two y-values y=15 and y=19 at x=9.

Therefore, the correct options are 2, 4, 6 and 7.

answer: it's a

step-by-step explanation:

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.