Given that 7 is a zero of h(x)=x^3-7x^2-3x+21, find the other zeros.

x= 7    x = ±√3

Step-by-step explanation:

h(x)=x^3-7x^2-3x+21

Factor by grouping

h(x) = x^2( x-7)  -3 (x-7)

Factor out an (x-7)

h(x) = (x-7)  ( x^2 -3)

Using the zero product property

0= (x-7)  ( x^2 -3)

x-7 =0     x^2 -3 =0

x=7     x^2 =3

x= 7    x = ±√3

answer: a numerical coefficient is a constant multiplier of the variables in a term. in the term -5x2y, the numerical coefficient is -5. in the expression ax2 + bx + c, the numerical coefficient of the x2 term is "a" and the numerical coefficient of the x term is "b".

step-by-step explanation:

the answer is b