The wings of some humming birds beat 52 times per second when hovering. if a hummingbird hovers for 35.5 seconds, how many times do its wings beat?

1846[

Step-by-step explanation:

Given : The number of times the wings of some humming birds beat in each second = 52

If a hummingbird hovers for 35.5 seconds then , the number of times the wings of humming birds beat in 35.5 seconds will be the product of 52 and 35.5

i.e.

Hence, the wings of humming bird beats 1846 times in 35.5 seconds when hovering.

correct answer:

i^31 = -i

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.