Darpana solved the equation s = StartFraction a + b + c Over 3 EndFraction for a. Her steps are shown below: 1. Multiply by 3: s = StartFraction a + b + c Over 3 EndFraction. 3 s = a + b + c. 2. Subtract b: 3 s minus b = a + b + c minus b. 3 s minus b = a + c. 3. Divide by c: StartFraction 3 s minus b Over c EndFraction = a. Which statement about Darpana's work is true? In step 1 she needed to divide by 3 rather than multiply. In step 2 she needed to add b rather than subtract. In step 3 she needed to subtract c rather than divide. Darpana solved the equation correctly.

Option (c) is correct.

Step-by-step explanation:

Given equation is :

The equation can be solved for a as follows :

Step 1.

Cross multiply the given equation

Step 2.

Now subtract b on both sides

3s-b = a+b+c-b

3s-b = a+c

Step 3.

Subtract c on both sides

3s-b-c=a+c-c

⇒ a=3s-b-c

The statement that is true for Darpana is " In step 3, she needed to subtract c rather than divide".

linear

step-by-step explanation:

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: