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Mathematics, 13.10.2020 23:01 Imthiccasf

F(x)=\begin{cases}x+3 & \text{ for }\hspace{10px} x<-5\phantom{\frac{1}{1}} \\ 1 & \text{ for }\hspace{10px} x=-5\phantom{\frac{1}{1}} \\ -\frac{4}{5}x-3 & \text{ for }\hspace{10px} x>-5\phantom{\frac{1^{1^1}}{1^{1 ^1}}}\end{cases} f(x)= ⎩ ⎪ ⎨ ⎪ ⎧ x+3 1 − 5 4 x−3 for x<−5 1 1 for x=−5 1 1 for x>−5 1 1 1 1 1 1

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F(x)=\begin{cases}x+3 & \text{ for }\hspace{10px} x<-5\phantom{\frac{1}{1}} \\ 1 & \text{...

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