Mathematics, 13.10.2020 21:01 chem1014

If x = log2a, y = logs, 2a, z = log1,3a: prove that xyz + 1 = 2yz. proof: Here, x = log2a, y = log 3,2a, z = log443a. Then
(2a)* = a (3a)y = 2a (4a)2 = 3a

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If x = log2a, y = logs, 2a, z = log1,3a: prove that xyz + 1 = 2yz. proof: Here, x = log2a, y = log...