The length of a rectangle is 5 in more than double the width

length of a rectangle is 5 more than twice the length. I believe

you mean the length of a rectangle is 5 more than twice the

width.

From the information given we can make two equations,

thus forming a system to solve. We know the perimeter

of a rectangle is 2(length + width) and area = length*width.

length of a rectangle is 5 more then twice the width:

L = 2w + 5

The perimeter is 130:

2(L+w) = 130

L+w = 65

Since we know L=2w+5 we can substitute that into 2nd equation

to solve for w

2w + 5 + w = 65

3w = 60

w = 20

L = 2w+5 = 45

The area is length*width = 20(45) = 900 square units

the correct answer is a.) bc< mn 5 stars if this you : )

step-by-step explanation:

da freeck kinda math is this just drop out

step-by-step explanation: